Groovy 学习笔记3 运行效率

王朝java/jsp·作者佚名  2006-01-09
宽屏版  字体: |||超大  

第一篇笔记里面,我说groovy运行的居然还满快的,其实是个误会了。我上次做八皇后还是在8080上面用basic做的,和现在奔四上面的groovy相比是没有意义的。特地又做了个对比试验:

queens.groovy

int q=9

int[] i=new int[q]

int count=0

long t = System.currentTimeMillis();

scan(0)

println("totle results:"+count)

println("totle time:"+(System.currentTimeMillis()-t));

def scan(n){

if (n==q){

println(i.toList())

count++

return

}

i[n]=0

while(i[n]<q){

i[n] = i[n]+1

if (check(n))

scan(n+1)

}

}

def check(n){

if (n>0)

for (j in 0..n-1)

if (i[j]==i[n] || i[j]-i[n]==j-n || i[j]-i[n]==n-j )

return false

return true

}

运行结果是:totle time:7271 (为了用groovy控制台运行的,直接用groovy命令运行还要慢一点)

java呢?

queens.java:

public class queens

{

static int q=9;

static int[] i=new int[q];

static int count=0;

public static void main(String[] args){

long t = System.currentTimeMillis();

scan(0);

System.out.println("totle results:"+count);

System.out.println("totle time:"+(System.currentTimeMillis()-t));

}

private static void scan(int n){

if (n==q){

for (int k=0;k<q;k++) System.out.print(i[k]+(k==q-1?"\n":","));

count++;

return;

}

i[n]=0;

while(i[n]<q){

i[n] = i[n]+1;

if (check(n)){

scan(n+1);

}

}

}

private static boolean check(int n){

int j=0;

while(j<n){

if (i[j]==i[n] || i[j]-i[n]==j-n || i[j]-i[n]==n-j ){

return false;

}

j++;

}

return true;

}

}

运行结果是:totle time:791

每次运行花费的时间略有不同,大致相差10倍左右。

能说这是脚本语言天生的缺陷吗?我们来看看同样是类似java语法的脚本语言javascript在IE里面的速度:

<SCRIPT LANGUAGE="JavaScript">

<!--

var q=9

var i=[]

var count=0

var d = new Date();

scan(0)

document.write("totle results:"+count+"<br>")

document.write("time used:"+(new Date()-d)+"<br>")

function scan(n){

if (n==q){

document.write(i+"<br>")

count++

return

}

i[n]=0

while(i[n]<q){

i[n] = i[n]+1

if (check(n)){

scan(n+1)

}

}

}

function check(n){

var j=0;

while(j<n){

if (i[j]==i[n] || i[j]-i[n]==j-n || i[j]-i[n]==n-j ){

return false

}

j++

}

return true

}

//-->

</SCRIPT>

运行结果是: time used:1241

只比java慢了不到一倍,看来groovy还差的太远了。

把groovy编译的class文件反编译了一下,看到groovy生成的代码效率确实是太低了,我们就看循环最内层的check函数把:

def check(n){

if (n>0)

for (j in 0..n-1)

if (i[j]==i[n] || i[j]-i[n]==j-n || i[j]-i[n]==n-j )

return false

return true

}

编译后变成

public Object check(Object obj)

{

if(ScriptBytecodeAdapter.compareGreaterThan(obj, new Integer(0)))

{

Object obj1 = null;

for(Iterator iterator = ScriptBytecodeAdapter.asIterator(ScriptBytecodeAdapter.createRange(new Integer(0), ScriptBytecodeAdapter.invokeMethod(obj, "minus", ((Object) (new Object[] {

new Integer(1)

}))), true)); iterator.hasNext();)

{

Object obj2 = iterator.next();

Object obj3 = null;

if(ScriptBytecodeAdapter.asBool(ScriptBytecodeAdapter.asBool(ScriptBytecodeAdapter.compareEqual(ScriptBytecodeAdapter.invokeMethod(ScriptBytecodeAdapter.getGroovyObjectProperty(this, "i"), "getAt", ((Object) (new Object[] {

obj2

}))), ScriptBytecodeAdapter.invokeMethod(ScriptBytecodeAdapter.getGroovyObjectProperty(this, "i"), "getAt", ((Object) (new Object[] {

obj

})))) || ScriptBytecodeAdapter.compareEqual(ScriptBytecodeAdapter.invokeMethod(ScriptBytecodeAdapter.invokeMethod(ScriptBytecodeAdapter.getGroovyObjectProperty(this, "i"), "getAt", ((Object) (new Object[] {

obj2

}))), "minus", ((Object) (new Object[] {

ScriptBytecodeAdapter.invokeMethod(ScriptBytecodeAdapter.getGroovyObjectProperty(this, "i"), "getAt", ((Object) (new Object[] {

obj

})))

}))), ScriptBytecodeAdapter.invokeMethod(obj2, "minus", ((Object) (new Object[] {

obj

})))) ? ((Object) (Boolean.TRUE)) : ((Object) (Boolean.FALSE))) || ScriptBytecodeAdapter.compareEqual(ScriptBytecodeAdapter.invokeMethod(ScriptBytecodeAdapter.invokeMethod(ScriptBytecodeAdapter.getGroovyObjectProperty(this, "i"), "getAt", ((Object) (new Object[] {

obj2

}))), "minus", ((Object) (new Object[] {

ScriptBytecodeAdapter.invokeMethod(ScriptBytecodeAdapter.getGroovyObjectProperty(this, "i"), "getAt", ((Object) (new Object[] {

obj

})))

}))), ScriptBytecodeAdapter.invokeMethod(obj, "minus", ((Object) (new Object[] {

obj2

})))) ? ((Object) (Boolean.TRUE)) : ((Object) (Boolean.FALSE))))

return Boolean.FALSE;

}

}

return Boolean.TRUE;

}

一切都是object,做任何事情都是invokeMethod,两个整数的比较居然要写将近400个字符的代码,光看代码量都可以吓倒我了。这是我们期待的脚本语言吗?

为了减少编码量要花费10倍的运行效率做代价,我认为这个代价太高了。还是等待groovy的继续改进吧。

 
 
 
免责声明:本文为网络用户发布,其观点仅代表作者个人观点,与本站无关,本站仅提供信息存储服务。文中陈述内容未经本站证实,其真实性、完整性、及时性本站不作任何保证或承诺,请读者仅作参考,并请自行核实相关内容。
© 2005- 王朝网络 版权所有