java实现URL带参数请求(get/post)

param 为aaa=111&bbb=222.....格式

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public static String sendGet(String url,String param)

{

String result = "";

try{

String urlName = url + "?"+param;//

URL U = new URL(urlName);

URLConnection connection = U.openConnection();

connection.connect();

BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));

String line;

while ((line = in.readLine())!= null)

{

result += line;

}

in.close();

}catch(Exception e){

System.out.println("没有结果！"+e);

}

return result;

}

public static String sendPost(String url,String param)

{

String result="";

try{

URL httpurl = new URL(url);

HttpURLConnection httpConn = (HttpURLConnection)httpurl.openConnection();

httpConn.setDoOutput(true);

httpConn.setDoInput(true);

PrintWriter out = new PrintWriter(httpConn.getOutputStream());

out.print(param);

out.flush();

out.close();

BufferedReader in = new BufferedReader(new InputStreamReader(httpConn.getInputStream()));

String line;

while ((line = in.readLine())!= null)

{

result += line;

}

in.close();

}catch(Exception e){

System.out.println("没有结果！"+e);

}

return result;

}