PL/SQL中如何传递字符串变量给in

王朝mssql·作者佚名  2006-11-24
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一个简单的存储过程,传递字符串变量作为参数,传递给过程中的in 子句;但似乎不起作用 。 代码如下

CREATE OR REPLACE PROCEDURE WSREVSECT_5

pSectNos varchar2,

pRetCode OUT varchar2

) AS

nCount number;

BEGIN

SELECT count(fksrev) into nCount FROM SREVSECT

WHERE sectno IN (pSectNos ) /* as in 'abc', 'xyz', '012' */;

pRetCode:=to_char(ncount);

End

it works -- the above is the same as

where sectno = pSectNos

though, not what you want. You want it to be:

where sectno in ( 'abc', 'xyz', '012' )

NOT:

where sectno in ( '''abc'', ''xyz'', ''012''' )

当直接使用select count(*) into .. from .. where sectno in (pSectNos) 的时候,相当于where sectno = pSectNos

which is effectively is (else you could never search on a string with commas and

quotes and so on -- it is doing the only logical thing right now).

You can do this:

SQL> create or replace type myTableType as table

of varchar2 (255);

2 /

Type created.

tkyte@dev8i]ops$tkyte@dev8i> create or replace

function in_list( p_string in varchar2 ) return myTableType

2 as

3 l_string long default p_string || ',';

4 l_data myTableType := myTableType();

5 n number;

6 begin

7 loop

8 exit when l_string is null;

9 n := instr( l_string, ',' );

10 l_data.extend;

11 l_data(l_data.count) :=

ltrim( rtrim( substr( l_string, 1, n-1 ) ) );

12 l_string := substr( l_string, n+1 );

13 end loop;

14

15 return l_data;

16 end;

17 /

Function created.

tkyte@dev8i]ops$tkyte@dev8i> select *

2 from THE

( select cast( in_list('abc, xyz, 012') as

mytableType ) from dual ) a

3 /

COLUMN_VALUE

------------------------

abc

xyz

012

tkyte@dev8i]ops$tkyte@dev8i> select * from all_users where username in

2 ( select *

3 from THE ( select cast( in_list('OPS$TKYTE, SYS, SYSTEM')

as mytableType ) from dual ) )

4 /

USERNAME USER_ID CREATED

------------------------------ ---------- ---------

OPS$TKYTE 23761 02-MAY-00

SYS 0 20-APR-99

SYSTEM 5 20-APR-99

使用array如上绑定变量in-list的时候,要注意sql语句的执行计划;因为在有的版本下,cbo无法估计in-list virtual table的行数,产生不正确的执行计划。

 
 
 
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