javascript下过滤数组重复值的代码

王朝html/css/js·作者佚名  2008-09-09
宽屏版  字体: |||超大  

<script language="javascript">

function getNoRepeat() {

return arguments[0].join('‖').match(/(\b[^‖]+\b)(?!.*‖\1\b)/ig);

}

var tmpArr = [1, 'a', 'ab', 'abc', 'd', 1.2, 'a+b', 'd', 'e', 5, 'a', 1, 'h', 'c', 'ab'];

var retArr = getNoRepeat(tmpArr);

alert(retArr);

</script>

<script>

alert("1,11,1.11,1111,111,11,1,1.11".match(/(\b\d+(?:\.\d+)?\b)(?!.*,\1\b)/g))

</script>

<script>

alert("123450,0,1,2,5,3,2,12,4,1,1,123450".match(/(\b\d+\b)(?!.*,\1(,|$))/ig))

</script>

<script>

alert("123450,0,1,2,5,3,2,12,4,1,1,123450".match(/(\b\d+\b)(?!(?:,[^,]+)*,\1(?:,|$))/ig))

</script>

<script>

var s = "0,1,2,5,3,2,12,4,1,1,123450";

var sTmp = (","+s.split(",").reverse().join(",")+",").replace(/,([^,]+)(?=,.*,\1,)/ig, '').split(",").reverse

().join();

sTmp = sTmp.substr(1, sTmp.length-2);

alert(sTmp)

</script>

<script>

var strArr = "123450,0,1,2,5,3,2,12,4,1,1,123450".split(",")

var str = ","

for(i = 0; i < strArr.length; i++)

{

if(str.indexOf("," + strArr[i] + ",") == -1)str += strArr[i] + ","

}

alert(str.substring(1,str.length - 1))

</script>

 
 
 
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